Practice question

Given: A 1700 kg truck accelerates at 1.5 m/s² for 4 s, then a 1.8 kg stone is dropped. What is the horizontal distance traveled by the stone in 2.5 s ? (Neglect air resistance) Formula: Truck’s velocity after 4 s : v = u + at = 0 + 1.5 × 4 = 6 m/s. Substitution & Calculation: Stone inherits this horizontal velocity upon drop. No horizontal forces act after drop (air resistance neglected). Distance: s = v × t = 6 × 2.5 = 15 m . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.