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#gravitational physics

6 public questions tagged with this topic.

What is the escape speed from a planet with mass 1.8×1024kg and radius 3.5×106m? (G\=6.67×10−11N m2/kg2)

ve = 2GMR. ve = 2×6.67×10−11×1.8×10243.5×106. ve = 6.861×107≈8.28×103m/s≈8.3km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.3 km/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

A satellite orbits Earth at 19RE from the center. What is its orbital speed? (g\=9.8m/s2,RE\=6.4×106m)

v = gRE2r. r = 19RE, v = 9.8×6.4×10619. v = 3.301×106≈1.82×103m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.8 × 10³ m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

A body is projected from Earth with 13km/s. What is its speed far away? (Escape speed = 11.2km/s)

12vi2−12ve2 = 12vf2. vf2 = (13)2−(11.2)2 = 169−125.44 = 43.56. vf = 43.56≈6.6km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.6 km/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

Why does the Moon’s orbital period relate to Earth’s mass?

Kepler’s third law (T2 = 4π2GMEr3) to satellites like the Moon, where the period T depends on Earth’s mass ME, the central body, determining the gravitational force strength. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Earth’s mass determines the force. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A satellite orbits Earth at 9RE from the center. What is its orbital speed? (g\=9.8m/s2,RE\=6.4×106m)

v = gRE2r. r = 9RE, v = 9.8×6.4×1069. v = 6.964×106≈2.64×103m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.6 × 10³ m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

What is the minimum speed to escape from 4RE from Earth’s center? (g\=9.8m/s2,RE\=6.4×106m)

ve = 2gRE24RE = 9.8×6.4×1062. ve = 3.136×107≈5.6×103m/s = 5.6km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.6 km/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.