Practice question
Question
A Wheatstone bridge with \( R_1 = 10 \, \Omega \), \( R_2 = 20 \, \Omega \), \( R_3 = 15 \, \Omega \), \(
R_4 = 30 \, \Omega \) has a \( 15 \, \text{V} \) battery across AC and a galvanometer (\( 10 \, \Omega
\)) across BD. What is the current through the galvanometer?
Explanation
**Wheatstone bridge balance** condition R₁/R₂ = R₃/R₄, R₄ = R₂ R₃/R₁, when galvanometer current zero, potentials at midpoints equal. At balance, no current through galvanometer, enabling precise resistance measurement independent of source voltage. Check balance: (R₁/R₂) = (10/20) = 0.5 , (R₃/R₄) = (15/30) = 0.5 . Bridge is balanced. Since balanced, I_g = 0 A . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 0 A,
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