Practice question

Given: A 9 Ω resistor dissipates 36 W of power. What is the current through it? These values define the system as per NCERT data. Formula: Power: P = I² R. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Rearrange: I = sqrtP/R . Substitute: I = sqrt36/9 = sqrt4 = 2 A . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.