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Question

A \( 18 \, \text{V} \) battery with negligible internal resistance is connected to a cubical network of
12 resistors, each \( 3 \, \Omega \). What is the total current?

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Explanation

**Cells combination** series ε_eq = Σ ε_i, r_eq = Σ r_i, parallel for identical cells ε_eq = ε, r_eq = r/n, n number of cells. Maximum current when external R = r_eq, power transfer theorem, explaining why matching resistances maximizes power. Equivalent resistance: Rₑq = (5/6) R = (5/6) × 3 = 2.5 Ω . Total current: I = (V/Rₑq) = (18/2.5) = 7.2 A . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 7.2 A,

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