Practice question
Question
In an isolated system of two capacitors initially charged and then connected in parallel with opposite
polarities, what happens to the final energy of the system compared to the initial energy?
Explanation
**Energy density** in electric field u = ½ ε E², ε = K ε₀, E = V/d, total energy U = u·volume = ½ ε E²·A d =½ ε A d·(V/d)²=½ ε A V²/d=½ C V², consistent. For parallel plate, E = V/d ≈10⁶ V/m for 400 V across 0.4 mm, u≈½×8.85×10⁻¹²×10¹²≈4.4 J/m³. When two capacitors are connected in parallel with opposite polarities, charges redistribute such that the net charge on the positive plates (and negative plates) adjusts to a new equilibrium. The initial energy stored in the capacitors ( U_i = (1/2) C₁ V₁² + (1/2) C₂ V₂² ) is greater than the final
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