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Question

A dipole with \( p = 8 \times 10^{-9} \, \text{C m} \) makes an angle of \( 60^\circ \) with a uniform
field \( E = 1 \times 10^5 \, \text{N/C} \). What is its potential energy?

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Explanation

**Relation E = -∇V** shows field points down potential gradient. For system of opposite charges close together, equipotential near midpoint between them has V≈0, but shape distorted, not spherical, reflecting superposition of potentials V = k q₁/r₁ + k q₂/r₂. U = -p E cos θ = -8 × 10⁻⁹ × 1 × 10⁵ × cos 60° . cos 60° = 0.5 , so U = -8 × 10⁻⁹ × 1 × 10⁵ × 0.5 = -4 × 10⁻⁴ J . Using V = kQ/r, U = k q₁q₂/r, E = -dV/dr, C = ε₀A/d, 1/C_eq series, C_eq = ΣC parallel, U = ½ C

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