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#x-coordinate

3 public questions tagged with this topic.

Rotational Motion Applications

Three particles of masses 3kg, 6kg, and 9kg are located at (0,1), (2,2), and (4,0) respectively. What is the x-coordinat

Formula: X = m1x1+m2x2+m3x3m1+m2+m3. Masses: 3,6,9kg; x-coordinates: 0,2,4. X = (3×0)+(6×2)+(9×4)3+6+9 = 0+12+3618 = 4818 = 2.67m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.67 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Rotational Motion Applications

Three particles of masses 5kg, 10kg, and 15kg are at (0,0), (2,4), and (6,2) respectively. What is the x-coordinate of t

Formula: X = m1x1+m2x2+m3x3m1+m2+m3. Masses: 5,10,15kg; x-coordinates: 0,2,6. X = (5×0)+(10×2)+(15×6)5+10+15 = 0+20+9030 = 11030≈3.67m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.67 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Conservation of Angular Momentum

Three particles of masses 2kg, 4kg, and 6kg are at (0,2), (3,0), and (1,4) respectively. What is the x-coordinate of the

Formula: X = m1x1+m2x2+m3x3m1+m2+m3. Masses: 2,4,6kg; x-coordinates: 0,3,1. X = (2×0)+(4×3)+(6×1)2+4+6 = 0+12+612 = 1812 = 1.5m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.5 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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