Practice question
Question
Three particles of masses 3kg, 6kg, and 9kg are located at (0,1), (2,2), and (4,0) respectively. What is the x-coordinate of their center of mass?
Explanation
Formula: X = m1x1+m2x2+m3x3m1+m2+m3. Masses: 3,6,9kg; x-coordinates: 0,2,4. X = (3×0)+(6×2)+(9×4)3+6+9 = 0+12+3618 = 4818 = 2.67m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.67 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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