Practice question
Question
Three particles of masses 5kg, 10kg, and 15kg are at (0,0), (2,4), and (6,2) respectively. What is the x-coordinate of their center of mass?
Explanation
Formula: X = m1x1+m2x2+m3x3m1+m2+m3. Masses: 5,10,15kg; x-coordinates: 0,2,6. X = (5×0)+(10×2)+(15×6)5+10+15 = 0+20+9030 = 11030≈3.67m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.67 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.