Practice question
Question
What is the time (in seconds) required to deposit 0.405 g of calcium from molten CaCl₂ using a current of 1.5 A? (Atomic mass of Ca = 40.5 g/mol, F = 96500 C/mol)
Explanation
Ca²⁺ + 2e⁻ → Ca . 1 mol Ca (40.5 g) requires 2F. Moles = (0.405/40.5) = 0.01 mol , Charge = 0.01 × 2 × 96500 = 1930 C . t = (Q/I) = (1930/1.5) = 1286.67 s .
Related blogs
Guides and insights connected to this topic
SARS-CoV-2 Coronavirus: Structure, Genome, Proteins, Replication, Pathogenesis, and Host Interaction
Coronavirus Overview Coronaviruses (CoVs) are enveloped viruses (surrounded by a lipid membrane derived from host cells), belonging to the s...
Coronavirus Structure, Genome, Replication, Symptoms, Pathogenesis, and Prevention
Structure of Coronavirus Coronaviruses (enveloped RNA viruses) fall in the virus family Coronaviridae, order Nidovirales. They are enveloped...
Cucumber Mosaic Virus (CMV): Structure, Genome, Symptoms, Disease Cycle and Management
Cucumber Mosaic Virus (CMV): Introduction and Importance Cucumber Mosaic Virus (CMV) (plant-infecting RNA virus) is one of the most economic...