Practice question
Question
A weak acid has Lambdam° = 350 S cm² mol⁻¹ and Lambdam = 17.5 S cm² mol⁻¹ at 0.05 M. What is the dissociation constant Ka ?
Explanation
α = (Lambdam/Lambdam°) = (17.5/350) = 0.05 . Ka = (α² c/1 - α) = (0.05² × 0.05/1 - 0.05) = (0.0025 × 0.05/0.95) = 1.316 × 10⁻⁴ .
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