In the estimation of sulphur, 0.25 g of a compound gave 0.583 g of BaSO₄. What is the percentage of sulphur?
Molar mass of BaSO₄ = 233 g/mol, S = 32 g/mol. Mass of S = (32/233) × 0.583 = 0.08 g. Percentage = (0.08/0.25) × 100 = 32%.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation