Practice question
Question
In the estimation of sulphur, 0.25 g of a compound gave 0.583 g of BaSO₄. What is the percentage of sulphur?
Explanation
Molar mass of BaSO₄ = 233 g/mol, S = 32 g/mol. Mass of S = (32/233) × 0.583 = 0.08 g. Percentage = (0.08/0.25) × 100 = 32%.
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