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#Dumas method

12 public questions tagged with this topic.

CHEMISTRY

In the Dumas method, 0.5 g of a compound gave 134.4 mL of N₂ at STP. What is the percentage of nitrogen? (Atomic mass: N

Given: In the Dumas method, 0.5 g of a compound gave 134.4 mL of N₂ at STP. What is the percentage of nitrogen? (Atomic mass: N = 14) These values define the system as per NCERT data. Formula: Mass of N₂ = 28 × 134.4/22400 = 0.168 g. This is standard NCERT relation. Substitution & Calculation: Mass of N = 0.168 g. Percentage = 0.168 × 100/0.5 = 33.6% . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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CHEMISTRY

In Dumas method, the nitrogen gas collected is measured at which condition?

The Dumas method measures N₂ volume, which is corrected to STP (0°C, 760 mm Hg) for calculation of nitrogen percentage. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the estimation of nitrogen by Dumas method, 0.4 g of a compound produces 84 mL of N₂ at STP, and in Carius method, 0.

Mass of N = (28/22400) × 84 = 0.105 g. Percentage = (0.105/0.4) × 100 = 26.25%. (Carius data is a distractor for chlorine.)

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

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Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Dumas method, 0.35 g of a compound gave 90 mL of N₂ at STP, and in Carius method, 0.35 g gave 0.574 g of AgBr. Wh

Mass of N = (28/22400) × 90 = 0.1125 g. Percentage = (0.1125/0.35) × 100 = 32.14% ≈ 32%. Carius data is for bromine, not relevant here.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

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