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Question

In the Dumas method, 0.3 g of a compound gave 70 mL of N₂ at STP. What is the percentage of nitrogen?

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Explanation

Mass of N = (28/22400) × 70 = 0.0875 g. Percentage = (0.0875/0.3) × 100 ≈ 29.17% ≈ 29%.

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