The Ka of CH₃COOH is 1.8 × 10⁻⁵ . What is the Kb of CH₃COO- at 298 K?
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , Kb = (1.0 × 10⁻¹⁴/1.8 × 10⁻⁵) ≈ 5.56 × 10⁻¹⁰ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Ionic Equilibrium - Acids Bases and pH and Ionization of Weak Acids Bases