Practice question
Question
The Ka of CH₃COOH is 1.8 × 10⁻⁵ . What is the Kb of CH₃COO- at 298 K?
Explanation
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , Kb = (1.0 × 10⁻¹⁴/1.8 × 10⁻⁵) ≈ 5.56 × 10⁻¹⁰ .
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