Practice question
Question
What is the standard emf of a cell with the reaction 2Al(s) + 3Cd²⁺(aq) → 2Al³⁺(aq) + 3Cd(s) ? (Given: E°Al³⁺/Al = -1.66 V , E°Cd²⁺/Cd = -0.40 V )
Explanation
E°cell = E°cathode - E°anode = -0.40 - (-1.66) = 1.26 V .
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