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E°cell = E°cathode - E°anode = -0.40 - (-1.66) = 1.26 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Corrosion and Applications of Electrochemistry
E°cell = E°cathode - E°anode = -0.40 - (-1.66) = 1.26 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Corrosion and Applications of Electrochemistry
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