Practice question
Question
Calculate the heat required to raise the temperature of 27 g of Al from 25°C to 45°C. (Molar heat capacity of Al = 24 J/mol·K, molar mass = 27 g/mol)
Explanation
Moles = 27 / 27 = 1 mol, Δ T = 20 K, q = nCpΔ T = 1 × 24 × 20 = 480 J = 0.48 kJ.
Discussion
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