Practice question
Question
Calculate the heat absorbed when 27 g of aluminum is heated from 25°C to 125°C at constant volume. (Cv = 22.4 J/mol·K, molar mass = 27 g/mol)
Explanation
Moles = 27 / 27 = 1 mol, Δ T = 125 - 25 = 100 K, qv = nCvΔ T = 1 × 22.4 × 100 = 2240 J = 2.24 kJ.
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