Practice question
Question
A solution of a non-volatile solute in 600 g of water freezes at -0.62°C. If the solute’s molar mass is 62 g/mol, what is the mass of the solute? ( Kf = 1.86 K kg mol⁻¹ )
Explanation
Δ Tf = Kf · m . 0.62 = 1.86 × (moles/0.6) . Moles = (0.62 × 0.6/1.86) ≈ 0.2 . Mass = 0.2 × 62 = 12.4 g .
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