Practice question
Question
A particle starts from rest with a constant acceleration of (−2i^+5j^)m/s2. What is the magnitude of its velocity after 3s?
Explanation
Velocity v=v0+at, with v0=0. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 16.16 m/s as the result, so option A is correct.
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