Practice question

**Energy distribution** shows maximum kinetic at equilibrium and maximum potential at extremes, sum constant. This relation enables calculation of amplitude, velocity at any displacement via v = ±√(2(E-U)/m), and understanding of energy storage in oscillating system for NEET problems. Total energy: E = (1/2) k A² = 0.5 × 300 × (0.08)² = 0.96 J . Potential energy: U = (1/2) k x² = 0.5 × 300 × (0.04)² = 0.24 J . Kinetic energy: K = E - U = 0.96 - 0.24 = 0.72 J . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and