Practice question

**Energy distribution** shows maximum kinetic at equilibrium and maximum potential at extremes, sum constant. This relation enables calculation of amplitude, velocity at any displacement via v = ±√(2(E-U)/m), and understanding of energy storage in oscillating system for NEET problems. Total energy: E = (1/2) k A² . 2 = 0.5 × 400 × A² ⇒ 2 = 200 A² ⇒ A² = 0.01 ⇒ A = 0.1 m . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 0.1 m follows, reflecting SHM dependence on amplitude A, ω and system parameters.