Practice question
Question
A body is projected with a speed of 20 m/s at 45°. What is the time to reach maximum height? (Take g = 10 m/s²)
Explanation
At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=20 m/s and g=10 m/s², h=20.0 m. This matches option A (2 s). Other options do not satisfy v²=u²+2as with correct signs.