Practice question
Question
A 0.3 M solution of Na₂SO₄ (assuming complete dissociation) has an osmotic pressure of 2.214 atm at a certain temperature. What is the temperature? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
For Na₂SO₄, i = 3 (2Na⁺ + SO₄²⁻). Pi = i · M · RT . 2.214 = 3 × 0.3 × 0.0821 × T . T = (2.214/0.9 × 0.0821) ≈ 30 K .
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