Practice question
Question
A 0.2 molal solution of a non-electrolyte in water has its boiling point elevated by 0.104°C. What is the value of Kb for water in this experiment?
Explanation
Δ Tb = Kb · m . 0.104 = Kb × 0.2 . Kb = (0.104/0.2) = 0.52 K kg mol⁻¹ .
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