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#redox

12 public questions tagged with this topic.

How many moles of electrons are required to reduce 1 mol of Cr³⁺ to Cr(s)?

Given: How many moles of electrons are required to reduce 1 mol of Cr³⁺ to Cr(s)? These values define the system as per NCERT data. Formula: Reaction: Cr³+ + 3e- -> Cr(s). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 3 moles of electrons are required per mole of Cr³⁺. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

Which reaction involves the displacement of hydrogen?

In Ca + 2Hâ‚‚O -> Ca(OH)2 + Hâ‚‚, Ca displaces H (+1 to 0), a redox displacement reaction. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

Which reaction involves the removal of an electropositive element as oxidation?

In 2K₄[Fe(CN)6] + H₂O₂ -> 2K₃[Fe(CN)6] + 2KOH, K is removed from K₄[Fe(CN)6], and Fe (+2 to +3) is oxidized. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

Which reaction demonstrates a redox process where a non-metal is both oxidized and reduced?

In S₈ + 12OH^- -> 4S^{2- + 2S₂O₃^{2- + 6H₂O, S (0) splits: -2 (reduced), +2 (oxidized), a disproportionation. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

How much charge in coulombs is required to reduce 1 mol of Al³⁺ to Al?

Given: How much charge in coulombs is required to reduce 1 mol of Al³⁺ to Al? These values define the system as per NCERT data. Formula: Charge = 3 × F = 3 × 96500 = 289500 C .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Reaction: Al³⁺ + 3e⁻ → Al(s), 3 moles of electrons per mole of Al. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.