17 public questions tagged with this topic.
ΔP = ρgh. ρ = 1.06×103kg/m3, g = 10m/s2, h = 0.18m. ΔP = 1.06×103×10×0.18 = 1908Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1908 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP = ρgh. ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 0.2m. ΔP = 13.6×103×9.8×0.2 = 26656Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.67 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP⋅A = mg. mg = 4.5×105×9.8 = 4.41×106N, A = 600m2. ΔP = 4.41×106600 = 7350Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 7350 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP⋅A = mg. mg = 4.0×105×9.8 = 3.92×106N, A = 600m2. ΔP = 3.92×106600 = 6533.33Pa≈6533Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6533 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP = ρgh. ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 0.25m. ΔP = 13.6×103×9.8×0.25 = 33320Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.33 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP⋅A = mg. mg = 2.0×105×9.8 = 1.96×106N, A = 400m2. ΔP = 1.96×106400 = 4900Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4900 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP⋅A = mg. mg = 2.8×105×9.8 = 2.744×106N, A = 480m2. ΔP = 2.744×106480 = 5716.67Pa≈5717Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5717 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP⋅A = mg. mg = 2.2×105×10 = 2.2×106N, A = 440m2. ΔP = 2.2×106440 = 5000Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5000 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP = ρgh. ρ = 13.6×103kg/m3, g = 10m/s2, h = 0.28m. ΔP = 13.6×103×10×0.28 = 38080Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.8 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP = ρgh. ρ = 806kg/m3, g = 10m/s2, h = 0.3m. ΔP = 806×10×0.3 = 2418Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2418 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP⋅A = mg, mg = 2.5×105×10 = 2.5×106N. A = 400m2. ΔP = 2.5×106400 = 6250Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6250 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
ΔP⋅A = mg. mg = 3.5×105×10 = 3.5×106N, A = 550m2. ΔP = 3.5×106550 = 6363.64Pa≈6364Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6364 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
