A solution contains 9 g of a solute (molar mass = 90 g/mol) in 450 mL of solution. What is the molarity?
Moles of solute = (9/90) = 0.1 mol . Volume = 450 mL = 0.45 L. Molarity = (0.1/0.45) ≈ 0.2222 M .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis