#manometer

Fluid Pressure, Pascal's Law and Manometers

A manometer with whole blood (ρ\=1.06×103kg/m3) shows a height difference of 0.18m. What is the pressure difference? (Ta

ΔP = ρgh. ρ = 1.06×103kg/m3, g = 10m/s2, h = 0.18m. ΔP = 1.06×103×10×0.18 = 1908Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1908 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Fluid Pressure, Pascal's Law and Manometers

A manometer with mercury (ρ\=13.6×103kg/m3) shows a height difference of 20cm. What is the pressure difference? (Take g\

ΔP = ρgh. ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 0.2m. ΔP = 13.6×103×9.8×0.2 = 26656Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.67 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Bernoulli's Theorem and Applications

A manometer with mercury (ρ\=13.6×103kg/m3) shows a height difference of 0.25m. What is the pressure difference? (Take g

ΔP = ρgh. ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 0.25m. ΔP = 13.6×103×9.8×0.25 = 33320Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.33 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Fluid Pressure, Pascal's Law and Manometers

A manometer with ethyl alcohol (ρ\=806kg/m3) shows a height difference of 0.26m. What is the pressure difference? (Take

ΔP = ρgh. ρ = 806kg/m3, g = 9.8m/s2, h = 0.26m. ΔP = 806×9.8×0.26 = 2055.08Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2055 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Fluid Pressure, Pascal's Law and Manometers

A manometer with seawater (ρ\=1.03×103kg/m3) shows a height difference of 0.22m. What is the pressure difference? (Take

ΔP = ρgh. ρ = 1.03×103kg/m3, g = 9.8m/s2, h = 0.22m. ΔP = 1.03×103×9.8×0.22 = 2220.68Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2200 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Surface Tension, Capillarity and Excess Pressure

A manometer with mercury (ρ\=13.6×103kg/m3) shows a height difference of 0.28m. What is the pressure difference? (Take g

ΔP = ρgh. ρ = 13.6×103kg/m3, g = 10m/s2, h = 0.28m. ΔP = 13.6×103×10×0.28 = 38080Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.8 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Viscosity, Stokes' Law and Reynolds Number

A manometer with ethyl alcohol (ρ\=806kg/m3) shows a height difference of 0.3m. What is the pressure difference? (Take g

ΔP = ρgh. ρ = 806kg/m3, g = 10m/s2, h = 0.3m. ΔP = 806×10×0.3 = 2418Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2418 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Bernoulli's Theorem and Applications

A manometer with water (ρ\=1000kg/m3) shows a height difference of 0.15m. What is the pressure difference? (Take g\=9.8m

ΔP = ρgh. ρ = 1000kg/m3, g = 9.8m/s2, h = 0.15m. ΔP = 1000×9.8×0.15 = 1470Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1470 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Equation of Continuity and Flow Rate

A manometer with seawater (ρ\=1.03×103kg/m3) shows a height difference of 0.19m. What is the pressure difference? (Take

ΔP = ρgh. ρ = 1.03×103kg/m3, g = 10m/s2, h = 0.19m. ΔP = 1.03×103×10×0.19 = 1957Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1957 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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