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Kw = [H+][OH-] = 2.9 × 10⁻¹⁴ . In pure water, [H+] = sqrt2.9 × 10⁻¹⁴ ≈ 1.7 × 10⁻⁷ , pH = -log(1.7 × 10⁻⁷) ≈ 6.77 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier
Kw = [H+][OH-] = 1.0 × 10⁻¹² , [H+] = sqrt1.0 × 10⁻¹² = 1.0 × 10⁻⁶ , pH = -log(1.0 × 10⁻⁶) = 6 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Homogeneous and Heterogeneous Equilibria and Applications of Equilibrium Constant
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