What is the cell potential at 298 K for Zn(s) | Zn²⁺(0.01 M) || Cu²⁺(0.1 M) | Cu(s) ? (Given: E°cell = 1.10 V )
Ecell = E°cell - (0.059/2) log ([Zn²⁺]/[Cu²⁺]) = 1.10 - (0.059/2) log (0.01/0.1) = 1.129 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Nernst Equation and Gibbs Energy and Equilibrium Constant