In 2Tl + I₂ → 2TlI, which species undergoes oxidation?
Tl (0) becomes +1 in TlI, losing electrons, while I (0 to -1) is reduced.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Redox Titrations and Equivalent Weight and Normality
#iodine
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In the reaction 2KI + Cl₂ → 2KCl + I₂, what is the oxidizing agent?
Cl₂ (0) gains electrons to become Cl− (-1), oxidizing I− to I₂.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
What is the oxidation number of iodine in I₂?
In its elemental form, I₂, iodine has an oxidation number of 0.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Balancing Redox Reactions - Oxidation Number Method and Half Reaction
The number of lone pairs on iodine in IF₅ is:
In IF₅ , iodine has 7 valence electrons, forms 5 bonds (10 electrons used), leaving 2 electrons as 1 lone pair in a sp³d² hybridized state.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Ionic Bonding - Lattice Enthalpy and Properties of Ionic Compounds
The hybridization of iodine in IF₅ is:
In IF₅ , iodine has 6 electron pairs (5 bonding, 1 lone), requiring sp³d² hybridization, forming a square pyramidal shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Hydrogen Bonding and Resonance and Dipole Moment
Thyroid hormones are lipid soluble mainly due to presence of:
Correct option is C, Two benzene rings. In Endocrinology, the accurate description is Two benzene rings, and that is what you should commit to memory. Keep the definition tight and the role clear — the functional job described in the stem is exactly what Two benzene rings does in Endocrinology. Then Two benzene rings is the answer you can defend. Check yourself by covering the options and writing the answer first, then matching the letter — that builds confidence. If the wording feels dense, translate it into everyday language first, then map that plain sentence back onto Two benzene rings. Remember that physiology questions reward precise language: name the process, the location, and the outcome, then match that to the option text.
Ref: Animal physiology is Unit 7 of the CSIR NET Life Science Syllabus, covering core body systems. It accounts for roughly 10% of the total marks in Sections B and C.