Skip to content
Login Register

#flow speed

3 public questions tagged with this topic.

Bernoulli's Theorem and Applications

A pipe’s cross-sectional area decreases from 0.04m2 to 0.01m2. If the speed at the larger end is 2.5m/s, what is the spe

Continuity equation: A1v1 = A2v2. A1 = 0.04m2, v1 = 2.5m/s, A2 = 0.01m2. v2 = A1v1A2 = 0.04×2.50.01 = 10m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details
Surface Tension, Capillarity and Excess Pressure

A spray tube (5cm2) has 25 holes of diameter 1.0mm. If the flow speed is 2.4m/min, what is the ejection speed?

A1v1 = A2v2, v1 = 2.4m/min = 0.04m/s, A1 = 5×10−4m2. Hole area: Ah = π(0.5×10−3)2, total A2 = 25×π×2.5×10−7≈1.963×10−5m2. v2 = 5×10−4×0.041.963×10−5≈1.02m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.02 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details
Equation of Continuity and Flow Rate

A spray tube (6cm2) has 30 holes of diameter 1.1mm. If the flow speed is 3.6m/min, what is the ejection speed?

A1v1 = A2v2, v1 = 3.6m/min = 0.06m/s, A1 = 6×10−4m2. Hole area: Ah = π(0.55×10−3)2, total A2 = 30×π×3.025×10−7≈2.851×10−5m2. v2 = 6×10−4×0.062.851×10−5≈1.26m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.3 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details