What is the emf of the cell Co(s) | Co²⁺(0.01 M) || Ag⁺(0.001 M) | Ag(s) at 298 K? (Given: E°Co²⁺/Co = -0.28 V , E°Ag⁺/A
E°cell = 0.80 - (-0.28) = 1.08 V . Ecell = 1.08 - (0.059/2) log ([Co²⁺]/[Ag⁺]²) = 1.08 - 0.0295 log (0.01/0.000001) = 1.08 - 0.177 = 0.903 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Variation of Conductivity with Concentration and Measurement