9 public questions tagged with this topic.
In [Cr(NH₃)2(en)2]3+, NH₃ is unidentate (2 ligands), and each ethane-1,2-diamine (en) is bidentate (2 donor atoms). Total = 2 + (2 × 2) = 6.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Werner's Theory and Definitions - Ligands Coordination Number
Ligands: aqua (H₂O), chlorido (Cl), alphabetically ordered. Cr’s oxidation state is +3 (since [Cr(H₂O)4Cl₂]+ balances NO₃−). Name: tetraaquadichloridochromium(III) nitrate.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Nomenclature of Coordination Compounds
[Cr(NH₃)6][Co(CN)6] swaps NH₃ and CN− between Co and Cr, showing coordination isomerism.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Isomerism - Optical Isomerism and Linkage Ionisation Solvate
x + 0 + 2(−1) = +1 → x = +3.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Isomerism - Optical Isomerism and Linkage Ionisation Solvate
Cr₃+ (d3) has t2g3, 3 unpaired electrons.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Isomerism - Optical Isomerism and Linkage Ionisation Solvate
[Cr(H₂O)3Cl₃] (octahedral, [Ma₃b3]) has 2 geometrical isomers: facial (fac) and meridional (mer).
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Isomerism - Geometrical Isomerism in Coordination Compounds
Cr₂+ with 5 NH₃ and 1 Cl− (6 ligands). EAN = 24 − 2 + 2 × 6 = 34.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Crystal Field Theory - CFT and Crystal Field Splitting and CFSE
In [Cr(en)2(H₂O)Cl]2+, en is bidentate (2 ligands).
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Crystal Field Theory - CFT and Crystal Field Splitting and CFSE
[Cr(NH₃)6]3+ (Cr₃+, d3) is octahedral with NH₃, using inner d orbitals for bonding, resulting in d2sp3 hybridization.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Bonding - Valence Bond Theory and Hybridisation
