What is the product when CH₃CH₂CHClCH₃ reacts with alcoholic KOH ?
Alcoholic KOH promotes elimination (E₂) in CH₃CH₂CHClCH₃ , forming CH₃CH=CHCH₃ (2-butene) as the major product per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions