Practice question

Given: What is the ll potential at 298 K for Ni(s) + 2Ag⁺(0.002 M) → Ni²⁺(0.160 M) + 2Ag(s) if E_{ll⁰ = 1.05 V ? These values define the system as per NCERT data. Formula: E_{ll = E_{ll⁰ - 0.059/2 log frac[Ni^{2+][Ag^{+]². This is standard NCERT relation. Substitution & Calculation: Q = 0.160/(0.002)² = 40000, log Q = 4.602 . E_{ll = 1.05 - 0.059/2 × 4.602 = 1.05 - 0.136 = 0.914 V approx 0.91 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.