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Question

What is the equilibrium constant for a cell reaction with E°cell = 0.46 V at 298 K involving 2 electrons?

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Explanation

E°cell = (0.059/n) log Kc . 0.46 = (0.059/2) log Kc , log Kc = 15.59 , Kc ≈ 3.9 × 10¹⁵ .

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