Practice question

Practice question

What is the cell constant if the resistance of a 0.05 M KCl solution is 100 Ω and its conductivity is 0.0065 S cm⁻¹?

Choose one · Correct answer highlighted

0.065 cm⁻¹ 0.65 cm⁻¹ Correct 6.5 cm⁻¹ 1.3 cm⁻¹

kappa = (cell constant/R) , 0.0065 = (cell constant/100) , cell constant = 0.65 cm⁻¹ .

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