Skip to content
New summer mock series is live Attempt timed papers for SSC, banking, and engineering entrances with updated syllabi for this season. View exams

Question

The molar conductivity of a 0.1 M KCl solution is 129 S cm² mol⁻¹. If the conductivity of the solution is 0.0129 S cm⁻¹, what is the concentration used in the calculation?

Options

Choose one · Correct answer highlighted

Explanation

Lambdam = (kappa × 1000/c) . 129 = (0.0129 × 1000/c) , so c = (12.9/129) = 0.1 M .