Limiting molar conductivity of CaCl₂ calculation

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What is the limiting molar conductivity of CaCl₂ in water at 298 K, given λ°Ca²⁺ = 119 S cm² mol⁻¹ , λ°Cl⁻ = 76.3 S cm² mol⁻¹ ?

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195.3 S cm² mol⁻¹ 152.6 S cm² mol⁻¹ 271.6 S cm² mol⁻¹ Correct 347.9 S cm² mol⁻¹

Lambdam° = λ°Ca²⁺ + 2 λ°Cl⁻ = 119 + 2 × 76.3 = 271.6 S cm² mol⁻¹ .

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