Practice question
Question
The dissociation constant of acetic acid is 1.78 × 10⁻⁵ mol L⁻¹ at 0.001 M concentration with molar conductivity 48.15 S cm² mol⁻¹. What is its Lambdam° ?
Explanation
α = sqrt(Ka/c) = sqrt(1.78 × 10⁻⁵/0.001) = 0.133 . α = (Lambdam/Lambdam°) , 0.133 = (48.15/Lambdam°) , Lambdam° = 390.5 S cm² mol⁻¹ .
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