Practice question
Question
The K_{sp of PbI₂ is 7.1 × 10⁻⁹. What is its solubility in water?
Explanation
Given:
The K_{sp of PbI₂ is 7.1 × 10⁻⁹. What is its solubility in water?
Formula:
PbI₂(s) <=> Pb²+ + 2I-, K_{sp = S · (2S)² = 4S³.
Substitution & Calculation:
4S³ = 7.1 × 10⁻⁹, S³ = 1.775 × 10⁻⁹, S approx 1.21 × 10⁻³M.
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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