Practice question

Given: The K_{sp of Hg₂Cl₂ is 1.3 × 10⁻¹⁸. What is its solubility in water? Formula: Hg₂Cl₂(s) <=> Hg₂²+ + 2Cl-, K_{sp = S · (2S)² = 4S³. Substitution & Calculation: 4S³ = 1.3 × 10⁻¹⁸, S³ = 3.25 × 10⁻¹⁹, S approx 6.88 × 10⁻⁷M. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.