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Practice question

Question

The K_{sp of Ag₂CO₃ is 8.1 × 10⁻¹². What is the molar solubility in water?

Options

Choose one · Correct answer highlighted

Explanation

Given: The K_{sp of Ag₂CO₃ is 8.1 × 10⁻¹². What is the molar solubility in water? These values define the system as per NCERT data. Formula: Ag₂CO₃(s) <=> 2Ag+ + CO₃²-, K_{sp = (2S)² · S = 4S³. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 4S³ = 8.1 × 10⁻¹², S³ = 2.025 × 10⁻¹², S approx 1.27 × 10⁻⁴ M. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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