Practice question

**Work calculation** isobaric W = P(V₂ - V₁), e.g., P=1 atm=1.013×10⁵ Pa ΔV=0.01 m³ W=1013 J. Isothermal W = n R T ln(V₂/V₁), for n=1 mol T=300 K V₂/V₁=2 W=1×8.314×300×ln2=1729 J, work done by gas during expansion, area under P-V curve. W = P Δ V , P V = μ R T . Δ V = 15 - 9 = 6 L . P = (μ R T)/(V₁) = (1.5 × 8.3 × 380)/(9) = 526 atm (unit correction needed).Directly: W = μ R T ((V₂ - V₁)/(V₁)) , but W = P Δ V . W = 1.5 × 8.3 × 380 =